(10x^2)+2x=9

Solution for (10x^2)+2x=9 equation:

(10x^2)+2x=9

We move all terms to the left:

(10x^2)+2x-(9)=0

a = 10; b = 2; c = -9;
Δ = b2-4ac
Δ = 22-4·10·(-9)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{91}}{2*10}=\frac{-2-2\sqrt{91}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{91}}{2*10}=\frac{-2+2\sqrt{91}}{20}
$